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Re: Physic help
- To: KellySt@aol.com, email@example.com, firstname.lastname@example.org, email@example.com, firstname.lastname@example.org, email@example.com, firstname.lastname@example.org, David@InterWorld.com, email@example.com, DotarSojat@aol.com, firstname.lastname@example.org, email@example.com
- Subject: Re: Physic help
- From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)
- Date: Sat, 04 May 1996 11:29:42 +0100
I yesterday posted this by accident only to Kelly:
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>Hi all you physics types. On my web page describing my explorer class'
> I have a table where I list various fusion fuel cycles. It lists the
>resulting energy in Mev. For those of us who arn't familure with
>translating Mev into anything, could someone tell me what the speed of the
>resulting particals is? Given that all the power in those reactions is
>contained in the resulting kinetic energy of the particals. This should be
>a simple calculation, and would certainly be a nice addition to the table.
>Assuming of course your half of and undergrate physics degree wasn't over
>15 years stale!
I'm a bit amazed you ask this because 2 paragraphs later you explain what an
electron Volt is.
So I assume the problem is in the calculation of the velocities.
I'll assume the velocities are relativistic, to make the formulas usable for
Kinetic energy (in Joules) of a particle with mass m (in kg) moving with
gamma = v gamma >= 1
SQRT(1 - ----)
K = M c (gamma - 1) K=kinetic energy
In fact this is all you need, but there is a bit of a problem, namely that
there is more than one particle in each reaction, and that sometimes not all
particles have the same mass. This makes that not all particles have the
same final speed, ofcourse one could figure out a mean velocity, but I'm not
sure how to do that best.
If I would do a very rough approximation, I would use the Watts/kg numbers
in your table (by the way it should be Joule/kg).
Since then the velocities wouldn't be relativistic at all I can simply use:
E = 0.5 m v^2
v = SQRT[2 E/m]
For 2.058E14 Joule/kg this would give 2E7 m/s or 0.067c
Oh to make the thing complete here the translation from eV to joule:
1 eV = 1.6E-19 Joule
Note that eV is a measure for energy and that in particle physics the mass
of a particle is often given in eV also (this according to E=mc^2).