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*To*: starship-design@lists.uoregon.edu*Subject*: starship-design: Yikes!*From*: wharton@physics.ucla.edu (Ken Wharton)*Date*: Thu, 31 Jul 1997 09:48:51 -0700*Reply-To*: wharton@physics.ucla.edu (Ken Wharton)*Sender*: owner-starship-design

>>dP/dM = c {n(1+2A)^0.5 -1}/A > >Is dP/dM equal to P/M ? Yes - Since E cancels you can make it as small as you want. And my P is really delta P; the change in momentum of the ship. >Mo=9.38Mf > >We both forgot the Logarithm! (did you lure me into that?) >This really makes the mass-ratios dramatic for low efficiencies... >(This also clarifies my doubts about the apparent low ratios.) Yes, that's my mistake. So now, for a 10% efficiency, you need a sail/ship\ ratio of 10^26!! Yikes and a half. Did someone say they could turn beamed power into electricity at a 90% or better conversion? So all we need is a way to turn electricity into a perfect beam with a 60% efficiency. Otherwise we'll have to sign off on this idea... Damn logarithm. Ken

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