[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

*To*: T.L.G.vanderLinden@student.utwente.nl, kgstar@most.magec.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@interworld.com, lparker@destin.gulfnet.com, bmansur@oc.edu, DotarSojat@aol.com*Subject*: Re: Explorer Power Gain Problem*From*: KellySt@aol.com*Date*: Fri, 15 Mar 1996 00:38:44 -0500

> >So, bottom line, is the NUMBER right. You only said the formula was > >correct. Did I misunderstand you? I keep getting 5E16W, not 5E9W. > The formula is right, but the number is only valid when the velocity of the > starship is 5 m/s. The problem with the document is that the meaning of the > number is not told. Now I remember. I calculated the power the drive system would need for a one secound boost, and assumed it would be consonstant for the flight. I.E. if it takes X watts to push the ship at a ship G for a secound. Multiply that by the number of secounds of boost to get to desired speed, and .... Given that the engine should need to output the same power, to accelerate the same mass, at the same rate, at diferent speeds. It seems like it should work. Kelly

**Follow-Ups**:**Re: Explorer Power Gain Problem***From:*Kevin C Houston <hous0042@maroon.tc.umn.edu>

- Prev by Date:
**Mail address problems** - Next by Date:
**Re: Laser Aperture Size** - Prev by thread:
**Re: Explorer Power Gain Problem** - Next by thread:
**Re: Explorer Power Gain Problem** - Index(es):