[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Explorer Power Gain Problem
- To: KellySt@aol.com, firstname.lastname@example.org, email@example.com, firstname.lastname@example.org, email@example.com, firstname.lastname@example.org, email@example.com, David@InterWorld.com, firstname.lastname@example.org, email@example.com, DotarSojat@aol.com
- Subject: Re: Explorer Power Gain Problem
- From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)
- Date: Thu, 14 Mar 1996 21:43:03 +0100
>The formula in Kellies Explorer page is correct. The same thing you asked
>about that 5 m/s, I asked Kelly some long time ago (so long that he probably
>doesn't remember it anymore (no offence)).
>So, bottom line, is the NUMBER right. You only said the formula was
>correct. Did I misunderstand you? I keep getting 5E16W, not 5E9W.
The formula is right, but the number is only valid when the velocity of the
starship is 5 m/s. The problem with the document is that the meaning of the
number is not told.
So, yes, use P = m a v to calculate the power needed to accelerate a mass
m when it is flying at a speed v.
!! Important note: this formula is only valid for beamed energy, this means
the power P is the power from a non-moving energy source.
So since you don't want to use any form of beamed energy, you aren't a step
further. If you want to use a selfsustained ship, use the numbers that I
resently sent to the group, or check out the "calc.txt" document (and the
DOS program "calc.zip" that comes with it).