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*To*: KellySt@aol.com, kgstar@most.magec.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, bmansur@oc.edu, DotarSojat@aol.com*Subject*: Re: Explorer Power Gain Problem*From*: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)*Date*: Thu, 14 Mar 1996 21:43:03 +0100

To Brian, >The formula in Kellies Explorer page is correct. The same thing you asked >about that 5 m/s, I asked Kelly some long time ago (so long that he probably >doesn't remember it anymore (no offence)). > >So, bottom line, is the NUMBER right. You only said the formula was >correct. Did I misunderstand you? I keep getting 5E16W, not 5E9W. The formula is right, but the number is only valid when the velocity of the starship is 5 m/s. The problem with the document is that the meaning of the number is not told. So, yes, use P = m a v to calculate the power needed to accelerate a mass m when it is flying at a speed v. !! Important note: this formula is only valid for beamed energy, this means the power P is the power from a non-moving energy source. So since you don't want to use any form of beamed energy, you aren't a step further. If you want to use a selfsustained ship, use the numbers that I resently sent to the group, or check out the "calc.txt" document (and the DOS program "calc.zip" that comes with it). Timothy

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