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*To*: bmansur <bmansur@oc.edu>, David <David@InterWorld.com>, hous0042 <hous0042@maroon.tc.umn.edu>, jim <jim@bogie2.bio.purdue.edu>, Kelly Starks x7066 MS 10-39 <kgstar@most.fw.hac.com>, "L. Parker" <lparker@destin.gulfnet.com>, rddesign <rddesign@wolfenet.com>, Steve VanDevender <stevev@efn.org>, "T.L.G.vanderLinden" <T.L.G.vanderLinden@student.utwente.nl>*To*: zkulpa <zkulpa@zmit1.ippt.gov.pl>*Subject*: Explorer Power Gain Problem*From*: Brian Mansur <bmansur@oc.edu>*Date*: Sat, 09 Mar 96 17:27:00 PST*Encoding*: 29 TEXT

>From Brian Kelly, I was looking over your explorer paper and the power section, trying to understand how you got a power gain of 1E9 W per second. Your equation went something like: P = F dx/dt = m*a*dx/dt The mass of the ship was 100E6 kg. The acceleration was 10m/s^2. The duration of acceleration was 1E7 seconds. You plugged in the numbers like this: 100E6kg * 10m/s^2 * 5m/s = 5E9W Where did that 5m/s come from. I thought dx/dt was a distance traveled in one second. My physics textbook tells me power is F * v where v is velocity. Since our average speed is 5E7 m/s (average between our terminal speed of 1E8 m/s and 0 m/s) the equation should look like this: 100E6kg * 10m/s^2 * 5E7m/s = 5E16W. If I'm right, that is a hefty difference in power gain which we couldn't hope to meet without loading tremendous amounts of fusion fuel. Please tell me that I'm the one who is wrong. Also, when I ran the numbers for K.E. using the relativity equation and the basic physics equation (these are on your explorer paper and I don't have time to write them here) I came up with a 100+ fold difference in power. Can you confirm this? Do you even have time to read this letter? :)

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