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RE: starship-design: scoops and sails and something to push against.
Kevin,
This diagram would be the ramjet or hybrid ramjet
>
> It seemed to me that you were talking about gathering the hydrogen in
> toward the ship, then expelling it again. ( fig. 1.) (Note missed
> hydrogen)
>
>
>
> H H H H H H H
> \ \ H | | | / /
> \ | | | H | | /
> \ \ \ | / H / / H
> H \ H | | | | | H /
> \ \ |H | | / /
> \ | \ | / | / H H
> H \ \ | | | / /
> \ || | || /
> H H \ V | V / H H
> \ \ | / / H
> H H \ \|/ /
> \ | / H
> \|/
> |||
> [S]
> [H]
> [I]
> [P]
> |||
> HHH
> HHH
> |||
> VVV
>
>
This one is the external accelerator
> Whereas I am proposing this: (fig 2)
>
>
> H H H
> | | H | H H
> V V | V | |
> H V H V V
> | H | H
> H V H | V | H
> | | V H V |
> V V | V
> V
> - - - - - - - - - - - - negative charges
> -----------[ship]-----------
> + + + + + + + + + + + + positive charges
> H H H
> | | H | H H
> V V | V | |
> H V H V V
> | H | H
> H V H | V | H
> | | V H V |
> V v | v
> V
>
The problem is how to generate two monopolar fields? If you simply use two
grids, your net thrust will be zero.
>
> Umm... Negative? By stripping away an electron, wouldn't it be
> positive? If I'm wrong, then reverse the charges on the above drawing.
>
I'm not sure, but I think you would end up with both positive and negative
ions in roughly equal amounts.
> not if you are swimming in a sea of energy capable of ionizing hydrogen
Umm. there is not really that much usable energy there for the taking.
Lee