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*To*: Shealiak@XS4ALL.nl*Subject*: Re: starship-design: Re: FTL travel*From*: STAR1SHIP@aol.com*Date*: Wed, 5 Apr 2000 22:53:41 EDT*CC*: starship-design@lists.uoregon.edu*Reply-To*: STAR1SHIP@aol.com*Sender*: owner-starship-design@lists.uoregon.edu

In a message dated 4/3/00 4:00:08 PM Pacific Daylight Time, Shealiak@XS4ALL.nl writes: > Hi Tom, > > >> gamma = 1/Sqrt[1-v^2/c^2] > > > >I can probably show you six or seven gamma formulas from the > >equation fields > > The one on your page <http://members.aol.com/tjac780754/indexC.htm> does > contain only v and c as well. (It misses the squareroot though.) > > Timothy Hey Timothy, I do not use the square root one as Einstein instructed it had problems of returning imaginary solutions of real numbers and not just imaginary numbers. He fixed the problem with a different derivative I was taught in 1968 at the FAA Academy. The field of equations at indexC.htm is a unified field where all equations are in the same system of measurements and more important where variables like v in different formulas that are not the same are defined and subscripted properly. In this manner standardized definitions are made and discussions do no start out with "no this means that and not this" As It was Einstein's Unified Field Theory that more real work could be accomplished If all spoke the same language-in such a manner different scientific disciplines like electronics, chemistry, physics, math...etc could have a single source field of equations to work from to derive equations to solve unknowns. If you think indexC is confusing you should see my electronics field of equations I will scan in when I find it. I use the American system of measurements my self so click on Mathcad's units of measurement and select those I am most conformable with as I make enough errors without adding conversion errors. I could not land on Mars if I mixed units of measurements ;) Checking my math. if E(kinteic)=1/2MV^2 and E=MC^2 then 1/2MV^2=E(kinetic)=E=MC^2 The energy required to send 100 tons of propellant at 1/10 light speed is said at E(kinetic)=1/2[100 tons times (c/10)^2] E(kinetic)=1/2(100 tons times c^2/100) To find the amount of Mass to be converted to the required energy E=MC^2 solving for M is M=E/C^2 therefore replacing E with calculated E(kinetic) of 1/2(100 tons times c^2/100) therefore M= [1/2(100 tons times c^2/100)]/C^2 and clearing first then second parenthesis M= 100 tons times c^2/200C^2 and canceling C^2 therefore M=100/200 tons or M= 1/2 ton of matter to convert to energy to propel 100 tons of propellant to 1/10 light speed. >From MeVe=MpVp since 1/2 ton is converted then only 99.5 tons of propellant reach 1/10 light speed. so for a five ton payload the payload velocity calculates to be Vp=MeVe/Mp placing the calculations in to solve Vp=99.5 tons times 1/10 C/5 tons solves to Vp=9.95C/5 solves to Vp=1.99 C Tom Profession- High Speed, High Energy Physics

**Follow-Ups**:**starship-design: Formula page***From:*Timothy van der Linden <Shealiak@XS4ALL.nl>

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