[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: USING A ELECTROMAGNETIC BEAM TO PROPELL A STARSHIP
- To: KellySt@aol.com, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, neill@foda.math.usu.edu, 101765.2200@compuserve.com, MLEN3097@Mercury.GC.PeachNet.EDU
- Subject: Re: USING A ELECTROMAGNETIC BEAM TO PROPELL A STARSHIP
- From: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)
- Date: Thu, 06 Jun 1996 23:15:25 +0100
Kevin wrote:
>> But what has the upper hand? The constructive or destructive side... (This
>> was the reason for my inquiry.)
>
>Both. Constructive in the direction of TC, destructive in other directions
Maybe I'll make a simulation about that some time.
>> I already thought this was the base of your misunderstanding. For what I
>> know (I'm not 100% certain) this method only increases resolution (in the
>> sense of larger angle deviations), but it does not decrease diffraction in
>> the same way.
>> The term interferometry points at the comparing of two parts of a wavefront.
>> The difference in phase is then used in calculations that increase the
>> resolution. I know it is a bit fague, but I don't have good literature about
>> it at the moment. (Feel free to attack me if you still feel you are right).
>
>ME? Attack? Never! *8^S
>However, If it can produce better resolution, does this help the "jitter"
>problem?
Don't think so, however, those phased arrays (as I think they work) are
probably doing the thing you want.
One can focus radiowaves (using interference), by placing antennas in a line
at specific distances. Note however that these single antennas are radiating
in all directions (in contrary to a laser).
I'll check it out in literature if I get a chance.
>> Oops, last time I told you that the Doppler effect was cancelled for the
>> people in the starship, I think I was mistaken there.
>> Note the following expression for the Doppler shift, after the arrow I've
>> rewritten it so that you can see that there is more than f/gamma in it.
>>
>> 2
>> Sqrt[1 - b ] f 1
>> f'= f -------------- (where b=v/c) --> f' = ------- -------
>> 1 + b gamma 1 + b
>>
>
>Hmm... so earth would need to roughly double output near the middle of the
>pulse?
>where b=.99
I guess so. I already thought a while about this (that's the reason for the
delay of the last letter). I'd feel more confident if someone would confirm
this.
Timothy