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*To*: KellySt@aol.com, hous0042@maroon.tc.umn.edu, T.L.G.vanderLinden@student.utwente.nl, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, rddesign@wolfenet.com, David@interworld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, sl0c8@cc.usu.edu, MLEN3097@Mercury.GC.PeachNet.EDU, 101765.2200@compuserve.com*Subject*: more physics (short)*From*: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39)*Date*: Wed, 29 May 1996 13:00:51 -0500

Sorry I was doing a bit more physics calculations for the Web pages and ran into a problem. So if you can verify my new numbers vs the old ones I'ld appreciate it. Kelly ======================================================================= Using the old equation p=1/2 M V^2 we get the power (in watts) = 1/2 Mass (in Kg) * (exaust velocity in meters/sec)^2 Given the fuel numbers show watts per Kg the equation shuffels around to: Exaust velocity (in Meters per secound) =sqrt (2 * Power) >> Did I mess this up? Yes I'm ignoring relativistic << Fuel --> Exhaust Watts / kg p + 11B --> 3 4He 6.926 E13 11,800,000 m/s De + 3He --> 4He + p 3.505 E14 26,500,000 m/s * 6Li + 6Li --> 3 4He (Combined) 1.596 E14 17,800,000 m/s ** 3He + 3He --> 4He + 2 p 2.059 E14 20,300,000 M/s *** This all seems pretty straight forward, but then I noticed we had previously come up with exaust velopcities of: ================================================================ Fuel type Exhaust speed Specific Impulse (Isp) p + 11B --> 3 4He 14,000,000 M/sec 1,400,000. seconds De + 3He --> 4He + p 6Li + 6Li --> 3 4He 21,000,000 M/sec 2,100,000. seconds 3He + 3He --> 4He + 2 p 24,000,000 M/sec 2,400,000. seconds So which numbers are corect, the first group or secound? Kelly ---------------------------------------------------------------------- Kelly Starks Internet: kgstar@most.fw.hac.com Sr. Systems Engineer Magnavox Electronic Systems Company (Magnavox URL: http://www.fw.hac.com/external.html) ----------------------------------------------------------------------

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