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more physics (short)
- To: KellySt@aol.com, hous0042@maroon.tc.umn.edu, T.L.G.vanderLinden@student.utwente.nl, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, rddesign@wolfenet.com, David@interworld.com, lparker@destin.gulfnet.com, DotarSojat@aol.com, sl0c8@cc.usu.edu, MLEN3097@Mercury.GC.PeachNet.EDU, 101765.2200@compuserve.com
- Subject: more physics (short)
- From: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39)
- Date: Wed, 29 May 1996 13:00:51 -0500
Sorry I was doing a bit more physics calculations for the Web pages and ran
into a problem. So if you can verify my new numbers vs the old ones I'ld
appreciate it.
Kelly
=======================================================================
Using the old equation p=1/2 M V^2 we get the
power (in watts) = 1/2 Mass (in Kg) * (exaust velocity in meters/sec)^2
Given the fuel numbers show watts per Kg the equation shuffels around to:
Exaust velocity (in Meters per secound) =sqrt (2 * Power)
>> Did I mess this up? Yes I'm ignoring relativistic <<
Fuel --> Exhaust Watts /
kg
p + 11B --> 3 4He 6.926 E13 11,800,000 m/s
De + 3He --> 4He + p 3.505 E14 26,500,000 m/s
*
6Li + 6Li --> 3 4He
(Combined) 1.596 E14 17,800,000 m/s
**
3He + 3He --> 4He + 2 p
2.059 E14 20,300,000 M/s
***
This all seems pretty straight forward, but then I noticed we had
previously come up with exaust velopcities of:
================================================================
Fuel type Exhaust speed Specific Impulse
(Isp)
p + 11B --> 3 4He 14,000,000 M/sec 1,400,000. seconds
De + 3He --> 4He + p
6Li + 6Li --> 3 4He 21,000,000 M/sec 2,100,000. seconds
3He + 3He --> 4He + 2 p 24,000,000 M/sec 2,400,000. seconds
So which numbers are corect, the first group or secound?
Kelly
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Kelly Starks Internet: kgstar@most.fw.hac.com
Sr. Systems Engineer
Magnavox Electronic Systems Company
(Magnavox URL: http://www.fw.hac.com/external.html)
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