Re: Physic help

[T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)]

Kelly wrote:

>The info was taken from a paper by Bussard on reactors using these fuels.
>The reactors converted virtuall all (99+%) of the fueles energy directly to
>electricity.  No shielding or cooling system included.
>
>I was impressed.
>
>Probably the random collisions will cause heat and light.  But not until
>its clear of the system (or the energy is converted to electricity).

Well like I wrote you before, I still haven't the faintest idea how the
Bussard engine works. Is there anyone who can tell me the principle (ie.
tell me more than that it uses fusion as initial energy source)?
(are there any good electronic references?)

>>                          End velocity -->
>>          +------+-------+-------+------+-------+--------+
>>          | 0.20 |  0.30 |  0.40 | 0.50 |  0.60 |  0.70  |
>>    +-----+------+-------+-------+------+-------+--------+
>>  f | 200 |  7.6 |  22.2 |  69.5 |  244 |  1032 |   5906 |
>>    | 250 |  9.7 |  31.9 | 114.6 |  467 |  2338 |  16422 |
>> || | 300 | 12.0 |  44.4 | 180.0 |  839 |  4896 |  41401 |
>> || | 350 | 14.6 |  60.2 | 272.7 | 1439 |  9662 |  96907 |
>> || | 400 | 17.6 |  79.8 | 401.4 | 2376 | 18191 | 213876 |
>> \/ | 450 | 21.0 | 104.1 | 577.2 | 3805 | 32958 | 449882 |
>>    | 500 | 24.7 | 133.8 | 813.9 | 5941 | 57820 | 908988 |
>>    +-----+------+-------+-------+------+-------+--------+
>>
>>   Where f is  c^2 / 2.058E14 = 439        (c=3E8 m/s)

>I was only calculating the ratio in the explorer craft for deceleration
>(acceleration fuel isn't carried by the ship).  With the
>velocities/specific impulse that was giving the fuel ration was far higher.
>???

But in your own calculations you didn't use a fusion fuel with f=257. You
used one with f=439, I did show that number just under the table, maybe you
have not seen it? When looking in the table for f=439, you'll see that the
number is somewhere near your own calculated ratio.

Timothy