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Re: Explorer Power Gain Problem
- To: Kevin C Houston <hous0042@maroon.tc.umn.edu>
- Subject: Re: Explorer Power Gain Problem
- From: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39)
- Date: Fri, 15 Mar 1996 13:33:19 -0500
- Cc: KellySt@aol.com, T.L.G.vanderLinden@student.utwente.nl, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, rddesign@wolfenet.com, David@interworld.com, lparker@destin.gulfnet.com, bmansur@oc.edu, DotarSojat@aol.com
At 12:11 PM 3/15/96, Kevin C Houston wrote:
>Kelly:
>> Now I remember. I calculated the power the drive system would need for a one
>> secound boost, and assumed it would be consonstant for the flight. I.E. if
>> it takes X watts to push the ship at a ship G for a secound. Multiply that
>> by the number of secounds of boost to get to desired speed, and ....
>>
>> Given that the engine should need to output the same power, to accelerate the
>> same mass, at the same rate, at diferent speeds. It seems like it should
>> work.
>
>Sorry to burst your bubble, but if this is a mass based fuel system, then
>the mass of the fuel tank is going down constantly, and therefore the
>total mass of the ship is not the same
I know, that was the other reason I droped that methould of power calculation.
Kelly
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Kelly Starks Internet: kgstar@most.fw.hac.com
Sr. Systems Engineer
Magnavox Electronic Systems Company
(Magnavox URL: http://www.fw.hac.com/external.html)
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