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*To*: Kevin C Houston <hous0042@maroon.tc.umn.edu>*Subject*: Re: Explorer Power Gain Problem*From*: kgstar@most.fw.hac.com (Kelly Starks x7066 MS 10-39)*Date*: Fri, 15 Mar 1996 13:33:19 -0500*Cc*: KellySt@aol.com, T.L.G.vanderLinden@student.utwente.nl, kgstar@most.fw.hac.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, rddesign@wolfenet.com, David@interworld.com, lparker@destin.gulfnet.com, bmansur@oc.edu, DotarSojat@aol.com

At 12:11 PM 3/15/96, Kevin C Houston wrote: >Kelly: >> Now I remember. I calculated the power the drive system would need for a one >> secound boost, and assumed it would be consonstant for the flight. I.E. if >> it takes X watts to push the ship at a ship G for a secound. Multiply that >> by the number of secounds of boost to get to desired speed, and .... >> >> Given that the engine should need to output the same power, to accelerate the >> same mass, at the same rate, at diferent speeds. It seems like it should >> work. > >Sorry to burst your bubble, but if this is a mass based fuel system, then >the mass of the fuel tank is going down constantly, and therefore the >total mass of the ship is not the same I know, that was the other reason I droped that methould of power calculation. Kelly ---------------------------------------------------------------------- Kelly Starks Internet: kgstar@most.fw.hac.com Sr. Systems Engineer Magnavox Electronic Systems Company (Magnavox URL: http://www.fw.hac.com/external.html) ----------------------------------------------------------------------

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