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*To*: kgstar <kgstar@most.fw.hac.com>*Subject*: Re: Explorer Power Gain Problem*From*: Brian Mansur <bmansur@oc.edu>*Date*: Mon, 11 Mar 96 15:18:00 PST*Cc*: bmansur <bmansur@oc.edu>, David <David@InterWorld.com>, hous0042 <hous0042@maroon.tc.umn.edu>, jim <jim@bogie2.bio.purdue.edu>, "L. Parker" <lparker@destin.gulfnet.com>, rddesign <rddesign@wolfenet.com>, Steve VanDevender <stevev@efn.org>, "T.L.G.vanderLinden" <T.L.G.vanderLinden@student.utwente.nl>*Encoding*: 58 TEXT

---------- From: kgstar To: Brian Mansur Cc: bmansur; David; hous0042; jim; Kelly Starks x7066 MS 10-39; L. Parker; rddesign; Steve VanDevender; T.L.G.vanderLinden Subject: Re: Explorer Power Gain Problem Date: Monday, March 11, 1996 8:45AM >From Brian >Kelly >Damn, I thought I caught up with all of these then I found some people sent >to my office but not my home!!! Brian. No more need to worry about any mail avalanches coming from me. I need to do school work and I'm limiting myself to a max of 1 hr. a day for e-mail response. Probably less actually and perhaps not every day even. >Brian >Your numbers plugged in like this for your Explorer power requirements for a >10m/s^2 acceleration. > >100E6kg * 10m/s^2 * 5m/s = 5E9W > >Where did that 5m/s come from. I thought dx/dt was a distance traveled in >one second. My physics textbook tells me power is F * v where v is >velocity. Since our average speed is 5E7 m/s (average between our terminal >speed of 1E8 m/s and 0 m/s) the equation should look like this: > >100E6kg * 10m/s^2 * 5E7m/s = 5E16W. >Kelly >5m/s is the amount of distence it would travel in the first second. The >equation was computing only the power needed for one secound of boost. I'm >not sure if the equation is set up right, but it would suggest your 5e16w >number for the full boost to .3c. Brian I'm starting to see a pattern to all of our starship design problems. However bad we think something is. Multiply that problem by a factor of E9 and that should keep us in the gremlin's ballpark (and in the solar system unfortunately). >Brian >If I'm right, that is a hefty difference in power gain which we couldn't >hope to meet without loading tremendous amounts of fusion fuel. Can you >confirm this? >Kelly >I can't confirm this, but I do know the energy numbers I worked out in the >Explorer page were sloppy. Brian Does ANYONE know the proper equations? I'll try to find time to ask my phsyics professor.

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