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*To*: KellySt@aol.com, kgstar@most.magec.com, stevev@efn.org, jim@bogie2.bio.purdue.edu, zkulpa@zmit1.ippt.gov.pl, hous0042@maroon.tc.umn.edu, rddesign@wolfenet.com, David@InterWorld.com, lparker@destin.gulfnet.com, bmansur@oc.edu*Subject*: Re: Another new? idea*From*: T.L.G.vanderLinden@student.utwente.nl (Timothy van der Linden)*Date*: Sat, 09 Mar 1996 17:15:28 +0100

>No I was woundering about the amount of wattage to the amount of momentum, or >wattage to specific impulse in a reaction mass. I'm woundering about using >the beam to run a microwave powered rocket, rather than a sail. Oh, why didn't you say that at once ;) I hope this is what you mean: Momentum/Energy (p/E) ratio: for photons: 1/c for mass : 1/c {v/(c-Sqrt[c^2-v^2])} if you know the velocity or 1/c Sqrt[U(U+2 m c^2)] if you know mass and kinetic energy where {v/(c-Sqrt[c^2-v^2])} is always bigger than 1 So if you have some energy and want to get the most momentum of it you could best use mass. Tim

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