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starship-design: Fwd: Is this a good address?
In a message dated 2/14/02 7:53:23 PM Pacific Standard Time, STAR1SHIP writes:
<< Subj: Re: Is this a good address?
Date: 2/14/02 7:53:23 PM Pacific Standard Time
From: STAR1SHIP
To: dan@lakeweb.net
In a message dated 2/13/02 10:24:51 PM Pacific Standard Time,
dan@lakeweb.net writes:
<<
Don't think I won't work out your problem. And as most of the
participants on sci.physics are interested in that chip on their
shoulder, maybe I'll get their first! (Is that a contradiction in
terms?) I've taken the simplistic view of SR for so long...
Thanks for all your time and effort. Maybe sci.physics can be a place to
learn from again. I'll do my best.
Dan.
>>
Thanks, for the kind words and offer to help Dan.
I need all the help I can get :).
The given problem is indeed simple containing 3 varibles v,a and t with a
and v given.
Here is some of my more recent notes and an apple(t) to boot.
Sent: 2/13/2002 10:00 PM
From: karlsagan Sent: 2/13/2002 9:34 PM
Mind you, I'm not, NOT, saying that you rocket motor couldn't reach a very
large percent of the speed of light. Just not go as fast as light or faster.
Much better Karl, note your rational thought marked in blue.
Note also
This applet lets you plan how long a trip will take on a rocket that travels
near the speed of light. You type the distance of the trip (measured in light
years) and the acceleration of the rocket (measured as a multiple of Earth's
gravity). The rocket will accelerate at that rate for half of the trip, then
decelerate at the same rate for the second half of the trip.
The time for the trip is measured in two ways: (1) As seen by a person who
stays behind on Earth, and (2) as measured by you on the ship. For your
convenience, space-sickness pills are available aft of the observation
lounge.
pluging in 4.25 light years to near star at 1 g acceleration the calculater
gives:
Trip length: 4.25 light years.
Acceleration: 1.0 g.
Time on earth: 5.8780560467144 years.
Time on ship: 3.544401860293398 years.
The distance between the earth and a near star does not change.
Next make some effort on your part to calculate with v = d/t and v'=d/t'
the different velocites as v=d/t measured by the earth observer and v'=d/t'
measured by the rocket man.
Calculate v as observed always less than c and v' can be C-Vx, C or C + Vx.
In the short trip given v'= C+Vx with Vx being some calculated velocity added
to C or subtacted from C.
Earth observation stops at C of C and C + V ship.
Calculate a and a' from v and v' above.
Use a' set at 1 g to exceed C wrt earth after earth observer stops seeing
rocket at C wrt earth.
Bon Voyage!
C-ship: Our Sturdy Craft
http://www.fourmilab.ch/cship/craft.html
The Relativistic Rocket Applet
http://ucsu.colorado.edu/~obrian/applets/Rocket/Voyage.html
Rocket simulations
http://www.execpc.com/~culp/rockets/rckt_sim.html
In addition;
>>
--- Begin Message ---
In a message dated 2/13/02 10:24:51 PM Pacific Standard Time, dan@lakeweb.net
writes:
<<
Don't think I won't work out your problem. And as most of the
participants on sci.physics are interested in that chip on their
shoulder, maybe I'll get their first! (Is that a contradiction in
terms?) I've taken the simplistic view of SR for so long...
Thanks for all your time and effort. Maybe sci.physics can be a place to
learn from again. I'll do my best.
Dan.
>>
Thanks, for the kind words and offer to help Dan.
I need all the help I can get :).
The given problem is indeed simple containing 3 varibles v,a and t with a and
v given.
Here is some of my more recent notes and an apple(t) to boot.
Sent: 2/13/2002 10:00 PM
From: karlsagan Sent: 2/13/2002 9:34 PM
Mind you, I'm not, NOT, saying that you rocket motor couldn't reach a very
large percent of the speed of light. Just not go as fast as light or faster.
Much better Karl, note your rational thought marked in blue.
Note also
This applet lets you plan how long a trip will take on a rocket that travels
near the speed of light. You type the distance of the trip (measured in light
years) and the acceleration of the rocket (measured as a multiple of Earth's
gravity). The rocket will accelerate at that rate for half of the trip, then
decelerate at the same rate for the second half of the trip.
The time for the trip is measured in two ways: (1) As seen by a person who
stays behind on Earth, and (2) as measured by you on the ship. For your
convenience, space-sickness pills are available aft of the observation
lounge.
pluging in 4.25 light years to near star at 1 g acceleration the calculater
gives:
Trip length: 4.25 light years.
Acceleration: 1.0 g.
Time on earth: 5.8780560467144 years.
Time on ship: 3.544401860293398 years.
The distance between the earth and a near star does not change.
Next make some effort on your part to calculate with v = d/t and v'=d/t'
the different velocites as v=d/t measured by the earth observer and v'=d/t'
measured by the rocket man.
Calculate v as observed always less than c and v' can be C-Vx, C or C + Vx.
In the short trip given v'= C+Vx with Vx being some calculated velocity added
to C or subtacted from C.
Earth observation stops at C of C and C + V ship.
Calculate a and a' from v and v' above.
Use a' set at 1 g to exceed C wrt earth after earth observer stops seeing
rocket at C wrt earth.
Bon Voyage!
C-ship: Our Sturdy Craft
http://www.fourmilab.ch/cship/craft.html
The Relativistic Rocket Applet
http://ucsu.colorado.edu/~obrian/applets/Rocket/Voyage.html
Rocket simulations
http://www.execpc.com/~culp/rockets/rckt_sim.html
In addition;
--- End Message ---